Graham Smith's suggestion
Ron Sun
rsun at athos.cs.ua.edu
Wed Nov 24 21:10:21 EST 1993
you can use a simpler means to achieve the same result, computationally.
you can use a distinct activation value to represent bindings.
this distinct value can be equated to phase.
so if two nodes receive the same value, then they are bound to the same
thing.
This scheme does not reuire [D[D[D
require temporal processing, but it can have all the
nice properties you mentioned.
--Ron
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